Math Solver 360

 55 Explanation: We need to find out the  fifth  number    from    consecutive integer numbers' sequence.                          Step-1: We have to have knowledge about integer number.An integer number does not have any fractional part.It can be positive or negative number. Now you have to understand about consecutive integer number.The difference between two consecutive integer numbers    is always 1.                    Step-2: Say,the first integer number is x. So, the second integer number will be x+ 1. Thus, the third consecutive integer number will be x+2  .Besides,the fourth integer number will be x+3 and the fifth number will be x+4 . Have a look here. The five consecutive integer numbers are x, x+1,x+2 ,x+3 ,x+4 respectively.                    Step-3: According to the conditions,the sum of 5 consecutive integer numbers will be 265.   So, we are getting the following equation   x +( x+1)+(x+2) +(x+3) +(x+4)  = 265 Or, 5x + 10 = 265 Or, 5x + 10 -10  = 265 - 10[ Deduct 10 f

4/57 Solution: 1/3 divided by 4 3/4 =1/3 ÷ 4 3/4 (Translating) =1/3 ÷(4×4+3)/4 (Mixed fraction to improper fraction) =1/3 ÷ (16+3)/4 =1/3 × 19/4 =1/3×4/19(Change of division sign and multiplied by the reciprocal fraction) =(1×4)/(3×19) [Multiply top to top and bottom to bottom numbers) =4/57 The answer for 1/ 3 divided by 4 3/4 i s 4/57.